I have been stuck on this question please help me solve it?

The following reaction is used in some self-contained breathing devices as a source of O2(g).
4KO2(s)+2CO2(g)⇌2K2CO3(s)+3O2(g)Kp=28.5at25∘C
Suppose that a sample of CO2(g) is added to an evacuated flask containing KO2(s) and equilibrium is established. The equilibrium partial pressure of CO2(g) is found to be 7.33×10−2 atm .

part A:

What is the equilibrium partial pressure of O2(g)?

part B:

What is the total gas pressure at the equilibrium?

Thank you

.......4KO2+2CO2⇌2K2CO3+3O2(g)

E.....solid..7.33E-2.solid...x
Kp = p(O2)^3/p(CO2)^2
Substitute and solve for pO2

Ptotal = pCO2 + pO2

hyik

To solve this problem, we can use the equilibrium constant expression and the given information to find the equilibrium partial pressure of O2(g) and the total gas pressure at equilibrium.

Part A: Equilibrium partial pressure of O2(g)

The balanced chemical equation for the reaction is:

4KO2(s) + 2CO2(g) ⇌ 2K2CO3(s) + 3O2(g)

The equilibrium constant expression for this reaction in terms of partial pressures is:

Kp = (P(O2))^3 / (P(CO2))^2

Given that Kp = 28.5 and P(CO2) = 7.33 × 10^-2 atm, we can rearrange the equation to solve for P(O2):

28.5 = (P(O2))^3 / (7.33 × 10^-2)^2

To isolate (P(O2))^3, we multiply both sides of the equation by (7.33 × 10^-2)^2:

28.5 × (7.33 × 10^-2)^2 = (P(O2))^3

Now, take the cube root of both sides to solve for P(O2):

P(O2) = ∛(28.5 × (7.33 × 10^-2)^2)

Evaluate this expression using a calculator to find the value of P(O2).

Part B: Total gas pressure at equilibrium

The total gas pressure at equilibrium is the sum of the partial pressures of all the gases present in the system. In this case, we need to calculate the partial pressure of O2 as found in Part A, as well as the partial pressure of CO2 given as 7.33 × 10^-2 atm.

Total gas pressure = P(O2) + P(CO2)

Using the values of P(O2) and P(CO2), calculate the sum to find the total gas pressure at equilibrium.

Remember to convert the units and use correct significant figures throughout the calculations.

I hope this helps you to solve the problem! Let me know if you have any further questions.