A potassium nitrate solution is prepared by dissolving 2.8 g of KNO3 in 27 mL of water. What is the concentration of this solution in units of grams of solute per 100 mL of solvent?
2.8 g x (100 mL/27 mL) = ? or if you want to do it by proportion it is
(2.8/27) = (x/100)
Solve for x.
10.37
To find the concentration in units of grams of solute per 100 mL of solvent, you need to calculate the weight/volume percent (w/v%).
The w/v% is calculated using the formula:
w/v% = (mass of solute / volume of solution) × 100
In this case, the mass of solute is given as 2.8 g and the volume of solution is given as 27 mL.
Substituting these values into the formula, we have:
w/v% = (2.8 g / 27 mL) × 100
Now, let's calculate the w/v%:
w/v% = (2.8 g / 27 mL) × 100
w/v% = 0.1037 × 100
w/v% = 10.37%
Therefore, the concentration of the potassium nitrate solution is 10.37 grams of solute per 100 mL of solvent.