A university drama production sold a total of 400 tickets for P18,500. If student tickets sold for P40 & guest tickets for P60, how many tickets of each type?

number of student tickets --- x

number of guest tickets ----- 400-x

solve for x

40x + 60(400-x) = 18500

A square shaped animal pen and a pen shaped like an equilateral triangle have an equal perimeters. Find the length of the sides of each if the sides of tje triangular pen are 16 less than twice a sidemif the square pen.

4s = 3t

t = 2s-16

the perimeters are both 96

To determine the number of student and guest tickets sold, we can use a system of equations. Let's represent the number of student tickets as 'x', and the number of guest tickets as 'y'.

Given that the total number of tickets sold is 400, we have the equation:
x + y = 400 (Equation 1)

We're also given that the total sales amounted to P18,500. The cost of each student ticket is P40, while the cost of each guest ticket is P60. Thus, we have the equation:
40x + 60y = 18500 (Equation 2)

To solve this system of equations, we can use one of several methods. Let's use the method of substitution:

Step 1: Solve Equation 1 for 'x':
x = 400 - y

Step 2: Substitute the value of 'x' in Equation 2:
40(400 - y) + 60y = 18500

Step 3: Simplify and solve for 'y':
16000 - 40y + 60y = 18500
20y = 2500
y = 125

Step 4: Substitute the value of 'y' into Equation 1 to find 'x':
x + 125 = 400
x = 400 - 125
x = 275

Therefore, there were 275 student tickets and 125 guest tickets sold by the university drama production.