Do the following calculations for a 1150 kg car. a. How much work must be done on the car to accelerate it from 0 to 60 km/h.

**** Hi I am looking for advice on my questions below. This is my attempt at answering them.. Am i at least on the right track?

Ek=1/2mv^2
=1/2(1150)(16.67)
=9.6x10^3J

b. If the car can do this is 13 s, what is the power of the motor?
P=W/t
=9.6x10^3/13s = 738Watts

c. If a breaking force of 500 N is applied, how long (time) does it take to stop the car.

Ft=mV
t=mV/F

t= (1150)(16.67)/ 500N = 38.34s

d. What distance does the car travel while braking?

fd=1/2mv^2

500*d= 1/2 (1150) (16.67)^2
500 *d= (575)(277.9)
d=1.6x10^5 / 500
d=320m

looks good

Your calculations seem to be generally correct. Let's go through each calculation to verify and explain the steps.

a. To calculate the work done on the car to accelerate it from 0 to 60 km/h, you correctly used the equation for kinetic energy, Ek = 1/2mv^2. However, the value of velocity (v) should be in meters per second (m/s) instead of kilometers per hour (km/h). So, we need to convert 60 km/h to m/s: 60 km/h = 60,000 m/3600 s = 16.67 m/s. Then you substituted the mass (m = 1150 kg) and calculated the kinetic energy (Ek = 1/2 * 1150 * 16.67^2 = 9.6 x 10^3 J). Your answer is correct.

b. To calculate the power of the motor, you can use the formula P = W/t, where W is the work done and t is the time taken. You have already calculated the work done as 9.6 x 10^3 J. You correctly substituted this value and the time taken (13 s) into the formula to calculate the power (P = 9.6 x 10^3 J / 13 s = 738 Watts). Your answer is correct.

c. To find the time it takes to stop the car with a braking force of 500 N, you can use the equation Ft = mV, where F is the force, t is the time, m is the mass, and V is the final velocity (0 m/s in this case since the car stops). You rearranged the equation to solve for time (t = mV/F) and substituted the values (m = 1150 kg, V = 16.67 m/s, F = 500 N) to find the time (t = 1150 x 16.67 / 500 = 38.34 s). Your answer is correct.

d. To calculate the distance traveled while braking, you used the formula fd = 1/2mv^2, which is incorrect. This formula calculates the work done, not the distance. To find the distance traveled, you can use the formula d = Vt, where d is the distance, V is the initial velocity (16.67 m/s), and t is the time taken (38.34 s). Substituting the values, we get d = 16.67 m/s x 38.34 s = 639.82 m. So the car travels approximately 640 meters while braking. Your answer is incorrect.

Please note that in real-world scenarios, the stopping distance may vary due to factors like road conditions and the effectiveness of the braking system.