A bird accelerates from 5 m/s,north to 25 m/s,north in 4s. A) What is the bird's acceleration vector? B) How far and in what direction does the bird travel in this interval? C) What is the bird's average velocity?

I will be happy to critique your thinking on this.

acceleartion=(finalveloicty-initialvelocity)/time
keep directon in those velocities.

average velocity=(finalvelocity+initialvelocity)/2

distance=average velocity * time.

a car travels in a straight line for 3 h at a constant speed of 53 km/h. what is the acceraleration? answer in units of m/s2.

To find the answers to these questions, we will use some basic kinematic equations. Let's break down each question step by step.

A) What is the bird's acceleration vector?
Acceleration is defined as the change in velocity divided by the change in time. In this case, the change in velocity is the final velocity minus the initial velocity, and the change in time is the time interval.

Given: Initial velocity (v0) = 5 m/s (north)
Final velocity (v) = 25 m/s (north)
Time interval (t) = 4 s

The acceleration can be calculated as:
acceleration (a) = (v - v0) / t = (25 m/s - 5 m/s) / 4 s = 20 m/s / 4 s = 5 m/s²

Therefore, the bird's acceleration vector is 5 m/s², pointing north.

B) How far and in what direction does the bird travel in this interval?
To determine the distance traveled by the bird, we need to calculate the displacement. Displacement is the change in position. Since the bird is moving in a single direction (north), the displacement will be equal to the distance traveled.

To calculate the displacement, we can use the equation:
displacement (d) = (v + v0) / 2 * t

Given: Initial velocity (v0) = 5 m/s (north)
Final velocity (v) = 25 m/s (north)
Time interval (t) = 4 s

displacement (d) = (25 m/s + 5 m/s) / 2 * 4 s = 30 m/s / 2 * 4 s = 60 m

Therefore, the bird travels a distance of 60 meters in the north direction during this interval.

C) What is the bird's average velocity?
Average velocity is the displacement divided by the time interval. In this case, we already found the displacement to be 60 meters, and the time interval is given as 4 seconds.

average velocity (v_avg) = displacement (d) / time interval (t) = 60 m / 4 s = 15 m/s

So, the bird's average velocity is 15 m/s, and it is in the north direction.