A certain gas is present in a 11.0L cylinder at 4.0 atm pressure. If the pressure I increased to 8.0 atm the volume of the gas decreased to 5.5L. Find the two constants Ki, the initial value of K, and the Kf, the final value of k, to verify whether the gas obeys boyles law.

AGASDF

8987

To verify whether the gas obeys Boyle's Law, we need to compare the initial and final values of K, the product of pressure and volume.

Boyle's Law states that the product of the pressure and volume of a gas is constant at constant temperature. Mathematically, it can be expressed as:

P1 * V1 = P2 * V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume

Given:
P1 = 4.0 atm
V1 = 11.0 L
P2 = 8.0 atm
V2 = 5.5 L

Let's calculate K1 (Ki):

K1 = P1 * V1
= 4.0 atm * 11.0 L
= 44.0 atm * L

So the initial value of K, K1 (Ki), is 44.0 atm * L.

Next, let's calculate K2 (Kf):

K2 = P2 * V2
= 8.0 atm * 5.5 L
= 44.0 atm * L

So the final value of K, K2 (Kf), is also 44.0 atm * L.

Now, let's verify if the gas obeys Boyle's Law by comparing the initial and final values of K:

K1 = K2

44.0 atm * L = 44.0 atm * L

Since the initial and final values of K are equal, we can conclude that the gas obeys Boyle's Law in this given scenario.

Note: The confirmation of Boyle's Law relies on the assumption that the temperature remains constant throughout the process.