Find the slope of a line that passes through (-2,-3) and (1,1).
a) 1/3
b) 1
c) 2
d) 4/3
(Y2-Y1)/(X2-X1) = (1+3) /(1+2)
= 4/3
By the way , that is algebra, and it is linear, but it is not "linear algebra"
Google "linear algebra "
:)
Here you go:
http://en.wikipedia.org/wiki/Linear_algebra
To find the slope of a line that passes through two given points, you can use the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
In this case, the two points are (-2, -3) and (1, 1).
Substituting the values into the formula:
m = (1 - (-3)) / (1 - (-2))
= (1 + 3) / (1 + 2)
= 4 / 3
Therefore, the slope of the line passing through (-2, -3) and (1, 1) is 4/3.
So, the correct answer is (d) 4/3.