A right triangle has a leg b of length 7 and a hypotenuse of length 11. What is the length of the other leg, a? Round to the nearest tenth, if necessary.
A) 2.0
B) 8.5
C) 13.0
D)9.6
7^2 + x^2 = 11^2
49 + x^2 = 121
x^2 = 72 = 36 * 2
x = 6 sqrt 2 = 8.48528
which is around 8.5
Now that was not even linear, never mind linear algebra LOL
@Damon can u please tell me the answers the quiz is rlly hard for me
So, B?
Yes the answer would be B
To find the length of the other leg, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, we are given that the hypotenuse (c) has a length of 11 and one of the legs (b) has a length of 7. Let's call the length of the other leg a.
Using the Pythagorean theorem, we have the equation:
a^2 + b^2 = c^2
Substituting the given values:
a^2 + 7^2 = 11^2
Simplifying:
a^2 + 49 = 121
Next, we can solve for a by subtracting 49 from both sides:
a^2 = 72
To find the value of a, we need to take the square root of both sides:
sqrt(a^2) = sqrt(72)
a = sqrt(72)
Using a calculator, we can find the approximate value of sqrt(72) to be approximately 8.5. Therefore, the length of the other leg (a) is approximately 8.5.
Rounding to the nearest tenth, the answer is B) 8.5.