A ball is projected horizontally from the top a hill with a velocity f 30mls. If it reaches the ground 5seconds later, the height of the hill is?

Wow. Deja vu.

S=ut + 1\2at*2

S=0×5 + 1\2 30×5×5
Divide through 2 by 30
S=0 + 6×5×5
Multiply together
S= 0 + 150
S=150m

S=ut + 1\2at*2

S=0×5 + 1\2×30×5×5
Divide through 2 by 30
S=0 + 6×5×5
Multiply together
S= 0 + 150
S=150m

To find the height of the hill, we need to use the formula for the horizontal motion of a projectile. In this case, since the ball is projected horizontally, there is no initial vertical velocity.

The formula for horizontal distance (range) is:

Range = Velocity * Time

In this case, the ball reaches the ground in 5 seconds and has a velocity of 30 m/s. Therefore, we can calculate the range:

Range = 30 m/s * 5 s
Range = 150 meters

Since the ball starts from the top of the hill and lands on the ground, the range is equal to the horizontal distance traveled, which is the same as the length of the hill.

Therefore, the height of the hill is 150 meters.