a father is four timrs as old as his son.5 years ago he was 7times as old as his son was.What is sons present age
now:
son --- x
father -- 5x
5 years ago:
son = x-5
father = 5x-5
5x-5 = 7(x-5)
solve for x
5x-5=7(x-5)=5x-5=7x-35=-5+35=7x-5x=30/a=2x=15=15+5=20=sons age=20
To find the son's present age, we need to solve a system of equations based on the given information.
Let's denote the father's present age as F, and the son's present age as S.
From the first statement, we know that the father is four times as old as his son, so we can write:
F = 4S (Equation 1)
From the second statement, we know that 5 years ago, the father was 7 times as old as his son. This can be expressed as:
(F - 5) = 7(S - 5) (Equation 2)
Now, we can solve the system of equations by substituting Equation 1 into Equation 2:
(4S - 5) = 7(S - 5)
First, distribute the 7 on the right side:
4S - 5 = 7S - 35
Next, move the variables to one side and the constants to the other side:
7S - 4S = -35 + 5
Simplify:
3S = -30
Divide both sides by 3 to solve for S:
S = -10
Since the son's age cannot be negative, there seems to be an error or inconsistency in the given information. Please double-check the details and provide accurate information to find the son's present age.