john is 4 years older than david and joe is 2 years younger than david . if the sum of their ages is 41. how old will john be in 8 years time?
David: X years old.
John: x+4 years old.
Joe: x-2 years old.
x + x+4 + x-2 = 41. Solve for x and add 8 years to John's age.
To find out how old John will be in 8 years, let's first determine their current ages.
Let's assume David's age is X.
According to the given information, John is 4 years older than David. So, John's age would be X + 4.
Joe, on the other hand, is 2 years younger than David. So, Joe's age would be X - 2.
Now, we know that the sum of their ages is 41:
X + (X + 4) + (X - 2) = 41.
Simplifying the equation:
3X + 2 = 41.
3X = 41 - 2.
3X = 39.
X = 39 / 3.
X = 13.
So, David's age is 13, John's age is 13 + 4 = 17, and Joe's age is 13 - 2 = 11.
To find out how old John will be in 8 years, we add 8 to his current age:
17 + 8 = 25.
Therefore, John will be 25 years old in 8 years time.