How many moles of chlorate ions, zinc ions, and oxygen atoms are present in 0.433 mol of zinc chlorate?
See your post on Al2(CO3)3 to see how to do this one.
Znclo3>>>> zn^+2 +clo3^-1
Zn ions :znclo3
1 : 1
O.43moles : 0.433moles
Znclo3 :clo3 ions
1 : 1
0.433moles : 0.433 moles
Moles of znclo3 = (6.023*10^23)(0.433)
=2.607959 *10^23 molecules/atoms
Oxygen atoms in znclo3= 3*(2.607959*10^23)
=7.823877*10^23 atoms
To determine the number of moles of chlorate ions, zinc ions, and oxygen atoms in 0.433 mol of zinc chlorate, we need to know the chemical formula of zinc chlorate.
The chemical formula of zinc chlorate is Zn(ClO3)2, which indicates that each formula unit of zinc chlorate contains one zinc ion (Zn2+), two chlorate ions (ClO3-), and six oxygen atoms (O).
To find the number of moles for each component:
1. Chlorate Ions (ClO3-):
The chemical formula Zn(ClO3)2 suggests that there are two chlorate ions in each formula unit of zinc chlorate. Therefore, the number of moles of chlorate ions can be calculated as follows:
Moles of Chlorate ions = 2 * Moles of Zinc chlorate
= 2 * 0.433 mol
= 0.866 mol
2. Zinc Ions (Zn2+):
The chemical formula Zn(ClO3)2 indicates that there is one Zn2+ ion in each formula unit of zinc chlorate. Therefore, the number of moles of zinc ions is the same as the number of moles of zinc chlorate.
Moles of Zinc ions = Moles of Zinc chlorate
= 0.433 mol
3. Oxygen Atoms (O):
The chemical formula Zn(ClO3)2 suggests that there are six oxygen atoms in each formula unit of zinc chlorate. Therefore, the number of moles of oxygen atoms can be calculated as follows:
Moles of Oxygen atoms = 6 * Moles of Zinc chlorate
= 6 * 0.433 mol
= 2.598 mol
In summary, for 0.433 mol of zinc chlorate:
- There are 0.866 mol of chlorate ions
- There are 0.433 mol of zinc ions
- There are 2.598 mol of oxygen atoms.
To determine the number of moles of chlorate ions, zinc ions, and oxygen atoms in 0.433 mol of zinc chlorate, we need to first determine the chemical formula of zinc chlorate.
The name "zinc chlorate" tells us that it consists of zinc cations (Zn^2+) and chlorate anions (ClO3^-). The chemical formula for zinc chlorate can be determined by balancing the charges of the ions. Since the charges must balance, we need two chlorate ions to balance the charge of one zinc ion,
So, the chemical formula of zinc chlorate is Zn(ClO3)2.
Now, we can determine the number of moles of each component:
1. Chlorate ions (ClO3^-):
Since there are two chlorate ions (ClO3^-) for every one formula unit of zinc chlorate (Zn(ClO3)2), the number of moles of chlorate ions is calculated by multiplying the total moles of zinc chlorate by the ratio of chlorate ions to zinc chlorate formula units:
Number of moles of chlorate ions = 2 * 0.433 mol = 0.866 mol.
2. Zinc ions (Zn^2+):
Since there is one zinc ion (Zn^2+) for every one formula unit of zinc chlorate (Zn(ClO3)2), the number of moles of zinc ions is equal to the total number of moles of zinc chlorate:
Number of moles of zinc ions = 0.433 mol.
3. Oxygen atoms:
To determine the number of oxygen atoms, we need to consider the number of oxygen atoms in each chlorate ion. Each chlorate ion contains three oxygen atoms.
Since there are two chlorate ions in one formula unit of zinc chlorate, the total number of oxygen atoms can be calculated by multiplying the number of moles of chlorate ions by the number of oxygen atoms per mole:
Number of moles of oxygen atoms = 2 * 3 * 0.433 mol = 2.598 mol.
So, in 0.433 mol of zinc chlorate:
- There are 0.866 mol of chlorate ions.
- There are 0.433 mol of zinc ions.
- There are 2.598 mol of oxygen atoms.