How many moles of carbonate ions, aluminum ions, and oxygen atoms are present in 39.0 g aluminum carbonate?
39 g Al2(CO3)3
mols Al2(CO3)3 = grams/molar mass = ?
There are 2 mols Al^3+ for every mole of Al2(CO3)3
There 3 mols of [CO3]^2- for every mole of Al2(CO3)3.
There are 9 mols O atoms for every mole Al2(CO3)3
hey guys my name is mike oxmaul
To determine the number of moles of carbonate ions, aluminum ions, and oxygen atoms in 39.0 g of aluminum carbonate, we need to use the molar mass of each component and the definition of mole:
1. Calculate the molar mass of aluminum carbonate:
Aluminum (Al) has a molar mass of 26.98 g/mol.
Carbonate (CO3) has a molar mass of 60.01 g/mol.
The molar mass of aluminum carbonate (Al2(CO3)3) can be calculated as follows:
2 * (molar mass of Al) + 3 * (molar mass of CO3)
Molar mass of Al2(CO3)3 = 2 * 26.98 g/mol + 3 * 60.01 g/mol
2. Calculate the number of moles of aluminum carbonate:
Number of moles = mass / molar mass
Number of moles = 39.0 g / (2 * 26.98 g/mol + 3 * 60.01 g/mol)
3. Calculate the number of moles of carbonate ions:
There are 3 carbonate ions in one molecule of aluminum carbonate (Al2(CO3)3).
Number of moles of carbonate ions = 3 * (number of moles of aluminum carbonate)
4. Calculate the number of moles of aluminum ions:
There are 2 aluminum ions in one molecule of aluminum carbonate (Al2(CO3)3).
Number of moles of aluminum ions = 2 * (number of moles of aluminum carbonate)
5. Calculate the number of moles of oxygen atoms:
There are 9 oxygen atoms in three carbonate ions (CO3) present in one molecule of aluminum carbonate (Al2(CO3)3).
Number of moles of oxygen atoms = 9 * (number of moles of carbonate ions)
Now you can substitute the value of the number of moles of aluminum carbonate into the formulas to find the number of moles of each component.
To find the number of moles of carbonate ions, aluminum ions, and oxygen atoms in 39.0 g of aluminum carbonate, we need to use the molar mass and stoichiometry.
First, we need to calculate the molar mass of aluminum carbonate (Al2(CO3)3):
- The molar mass of aluminum (Al) is 26.98 g/mol.
- The molar mass of carbonate (CO3) is (12.01 g/mol for carbon + 3 * 16.00 g/mol for oxygen) = 60.01 g/mol.
So, the molar mass of aluminum carbonate is: 2 * 26.98 g/mol + 3 * 60.01 g/mol = 233.99 g/mol.
Next, let's determine the number of moles of aluminum carbonate using its molar mass:
Number of moles = mass of substance / molar mass
Number of moles = 39.0 g / 233.99 g/mol = 0.1667 mol (rounded to four decimal places).
Now, we can use the stoichiometry of the compound to determine the number of moles of carbonate ions, aluminum ions, and oxygen atoms in 0.1667 mol of aluminum carbonate:
- From the chemical formula Al2(CO3)3, we can see that there are 3 moles of carbonate ions per 1 mole of aluminum carbonate. Therefore, there are 0.1667 mol * 3 = 0.5001 mol of carbonate ions.
- From the chemical formula Al2(CO3)3, we can see that there are 2 moles of aluminum ions per 1 mole of aluminum carbonate. Therefore, there are 0.1667 mol * 2 = 0.3334 mol of aluminum ions.
- From the chemical formula Al2(CO3)3, we can see that there are 9 moles of oxygen atoms per 1 mole of aluminum carbonate (3 from carbonate and 6 from aluminum oxide). Therefore, there are 0.1667 mol * 9 = 1.5003 mol of oxygen atoms.
In summary:
- The number of moles of carbonate ions in 39.0 g of aluminum carbonate is approximately 0.5001 mol.
- The number of moles of aluminum ions in 39.0 g of aluminum carbonate is approximately 0.3334 mol.
- The number of moles of oxygen atoms in 39.0 g of aluminum carbonate is approximately 1.5003 mol.