to make a sodium chloride solution of the same molarity as household bleach (as determined in question 1) how many grams of salt would be needed for every 100 ml of solution
question 1 answer: 0.871 M
9.8
0.871
To determine the mass of salt needed for a sodium chloride solution with the same molarity as household bleach (0.871 M), we need to calculate the number of moles of sodium chloride (NaCl) required.
Molarity (M) is defined as moles of solute per liter of solution. Therefore, we need to convert the volume of solution (100 ml) into liters.
1 liter = 1000 ml
So, 100 ml is equal to 100/1000 = 0.1 liters.
Now, we can calculate the number of moles of sodium chloride using the molarity and volume of solution:
Moles of NaCl = Molarity × Volume of solution
Moles of NaCl = 0.871 M × 0.1 liters
Moles of NaCl = 0.0871 moles
Finally, we can convert moles to grams using the molar mass of sodium chloride, which is 58.44 g/mol:
Mass of NaCl = Moles of NaCl × Molar mass of NaCl
Mass of NaCl = 0.0871 moles × 58.44 g/mol
Mass of NaCl = 5.08 g (rounded to two decimal places)
Therefore, you would need approximately 5.08 grams of sodium chloride for every 100 ml of solution to make a sodium chloride solution of the same molarity as household bleach.
To determine how many grams of salt would be needed to make a sodium chloride solution of the same molarity as household bleach, you first need to understand the concept of molarity.
Molarity (M) is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution. It is calculated using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
In this case, you are given the molarity of the household bleach solution, which is 0.871 M. To convert this molarity to grams of solute per 100 ml of solution, you need to follow these steps:
Step 1: Convert ml to liters:
Since the given volume is 100 ml, you need to convert it to liters by dividing by 1000:
100 ml / 1000 = 0.1 liters
Step 2: Use the molarity formula to calculate the moles of solute:
Molarity (M) = moles of solute / volume of solution (in liters)
Rearranging the formula to solve for moles of solute, we have:
moles of solute = Molarity (M) * volume of solution (in liters)
moles of solute = 0.871 M * 0.1 liters
moles of solute = 0.0871 moles
Step 3: Convert moles to grams:
To convert moles to grams, you need to know the molar mass of sodium chloride (NaCl). The molar mass of NaCl is 58.44 g/mol. Multiply the moles of solute by the molar mass to get the grams of solute:
grams of solute = 0.0871 moles * 58.44 g/mol
grams of solute = 5.09 grams (rounded to two decimal places)
Therefore, you would need 5.09 grams of salt for every 100 ml of solution to make a sodium chloride solution with the same molarity as household bleach.