A ball is droped out of a window of a tall building. If it hists the ground 3.5s later, how high aboe the ground is the window?
the distance in metres is 4.9t^2 (from physics), where t is seconds and d is metres.
so the distance is 4.9(3.5)^2 or appr. 60 metres
h=1/2 g t^2
To find out how high above the ground the window is, we can use the equations of motion. When an object is in free fall, its motion can be described by the following equation:
h = (1/2) * g * t^2
Where:
h = height (above the ground)
g = acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t = time
In this case, the ball took 3.5 seconds to hit the ground. We can plug this value into the equation to find the height of the window:
h = (1/2) * 9.8 * (3.5^2)
Simplifying the calculation:
h = 0.5 * 9.8 * 12.25
h = 59.45 meters
Therefore, the window is approximately 59.45 meters above the ground.