A number exceeds another by 4 and their sum is 32.Find the two numbers .

x+(x+4) = 32

x+x+4 = 32
2x + 4 =32
2x =32-4
2x =28
x = 28 ÷4
x = 14
x+4 =14 +4
X+4 =18
RESULT :
The two numbers are 14 and 18

If x = one number, then the other is x+4.

x + x+4 = 32

Solve for x.

Let's assume that the smaller number is x.

According to the given information, the larger number exceeds x by 4. So the larger number can be expressed as (x + 4).

The sum of the two numbers is 32. Therefore, we can write the equation: x + (x + 4) = 32.

Combining like terms, we have: 2x + 4 = 32.

Subtracting 4 from both sides of the equation, we get: 2x = 28.

Dividing both sides of the equation by 2, we find: x = 14.

So, the smaller number is 14, and the larger number (which exceeds the smaller number by 4) is 14 + 4 = 18.

Therefore, the two numbers are 14 and 18.

To find the two numbers, let's represent them as variables.

Let's call the first number "x" and the second number "y."

Based on the given information, we can create two equations:

Equation 1: "A number exceeds another by 4":
x = y + 4

Equation 2: "Their sum is 32":
x + y = 32

Now, we have a system of two equations with two unknowns. We can solve this system of equations to find the values of x and y.

Let's use the substitution method:

1. Start by solving Equation 1 for x:
x = y + 4

2. Substitute this expression for x in Equation 2:
(y + 4) + y = 32

3. Simplify the equation:
2y + 4 = 32

4. Move the constant term to the other side of the equation:
2y = 32 - 4
2y = 28

5. Divide both sides of the equation by 2:
y = 28/2
y = 14

Now, we have found the value of y, which is 14.

6. Substitute the value of y back into Equation 1 to find x:
x = y + 4
x = 14 + 4
x = 18

So, the two numbers are 18 and 14.