calculate the netforrce on q2?

calculate the net force on q3?
q1=+3.0 MC
q2=+3.0MC
q3=-6.0MC

q1-------20cm-------------q2
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50 cm
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q3

Hey, just use Coulomb's Law

F = k Q1 Q2 / d^2

if like charges, repel
if opposite signs, attract

see:
http://en.wikipedia.org/wiki/Coulomb's_law

And remember, you're adding VECTORS. You can't just add the two numbers. They have directions as well.

To calculate the net force on q2, we need to consider the electric forces exerted by both q1 and q3 on q2. The equation to calculate the electric force between two charges is given by Coulomb's law:

F = k * |q1 * q2| / r^2

Where:
- F is the magnitude of the electric force between the charges
- k is the electrostatic constant, approximately 9.0 x 10^9 Nm^2/C^2
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges.

In this scenario, we have:
- q1 = +3.0 MC (mega-coulombs)
- q2 = +3.0 MC (mega-coulombs)

To find the net force on q2, we need to consider the forces exerted by q1 and q3 separately and then add them vectorially.

First, let's calculate the force exerted by q1 on q2:

Distance between q1 and q2 = 20 cm = 0.20 m (converted to meters)

F1 = k * |q1 * q2| / r^2
= (9.0 x 10^9 Nm^2/C^2) * |(3.0 x 10^6 C) * (3.0 x 10^6 C)| / (0.20 m)^2

Now, we need to convert the charge from Coulombs to C using the fact that 1 MC (mega-coulomb) = 1 x 10^6 C (coulombs).
= (9.0 x 10^9 Nm^2/C^2) * |(3.0 x 10^6 x 10^6 C) * (3.0 x 10^6 x 10^6 C)| / (0.20 m)^2

Simplifying the equation, we get:

F1 = (9.0 x 10^9 Nm^2/C^2) * 3.0^2 x 10^12 / 0.20^2

Next, let's calculate the force exerted by q3 on q2:

Distance between q3 and q2 = 50 cm = 0.50 m (converted to meters)

F3 = k * |q2 * q3| / r^2
= (9.0 x 10^9 Nm^2/C^2) * |(3.0 x 10^6 C) * (6.0 x 10^6 C)| / (0.50 m)^2

Again, we need to convert the charge from Coulombs to C:

F3 = (9.0 x 10^9 Nm^2/C^2) * |(3.0 x 10^6 x 10^6 C) * (6.0 x 10^6 x 10^6 C)| / (0.50 m)^2

Simplifying the equation, we get:

F3 = (9.0 x 10^9 Nm^2/C^2) * 3.0 x 6.0 x 10^12 / 0.50^2

Now, we can calculate the net force (F_net) on q2 by adding the forces F1 and F3 vectorially:

F_net = F1 + F3

After performing the calculations, you will get the net force on q2.