If you jump off a 10 meter cliff on the Moon, and the acceleration of gravity is 1.6 m/s^2. How fast are you going when your feet hit the bottom of the cliff?
well, recall that v = √(2as)
so, plug in your a and s.
So is the answer 5.6
So when it asks how fast are you going when your feet hit the bottom of the cliff. My answer would be 5.6 meters?
sqrt ( 2*1.6*10) = 4 sqrt 2
= 5.66 m/s
To determine the speed when your feet hit the bottom of the cliff on the Moon, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
- v is the final velocity (what we want to find)
- u is the initial velocity (which is 0 m/s since you start from rest)
- a is the acceleration due to gravity (which is given as 1.6 m/s^2)
- s is the displacement (distance fallen from the cliff, which is 10 meters)
Now, let's substitute the given values into the equation:
v^2 = 0^2 + 2 * 1.6 * 10
Simplifying further:
v^2 = 0 + 32
v^2 = 32
To find the value of v, we take the square root of both sides of the equation:
v = √32
Calculating the square root, we find:
v ≈ 5.7 m/s
So, when your feet hit the bottom of the 10-meter cliff on the Moon, you would be traveling at approximately 5.7 meters per second.