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A newspaper carrier has $5.30 in change. He has ten more quarters than dimes but two times as many nickles as quarters. How many coins of each type does he has?

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  1. number of dimes --- x
    number of quarters -- x+10
    number of nickels = 2(x+10)

    now for the "value":
    10x + 25(x+10) + 5(2(x+10)) = 530

    solve for x, then plug into my definitions.

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