I need help in the formula to calculate these types of problems
125ml of 0.43M of HCl + 17ml of 1.8M HCl
Calculate the concentrations of solutions resulting from the mixture
divide the total moles by the total L
moles ... (.125 * .43) + (.017 * 1.8)
Liters ... .125 + .017
To calculate the concentrations of solutions resulting from the mixture, you can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution 1
V1 = initial volume of the solution 1
C2 = final concentration of the solution 2
V2 = final volume of the solution 2 (which is the sum of initial volumes of both solutions)
Let's solve the problem step by step:
1. Calculate the final volume:
V2 = V1 + V2 = 125 ml + 17 ml = 142 ml
2. Calculate the amount of HCl in each solution separately:
For the first solution 1:
Amount of HCl in solution 1 = C1 * V1 = 0.43 M * 125 ml
For the second solution 2:
Amount of HCl in solution 2 = C2 * V2 = 1.8 M * 17 ml
3. Calculate the final concentration of the mixture:
C2 = (Amount of HCl in solution 1 + Amount of HCl in solution 2) / V2
Now, you can substitute the values into the formula to find C2:
C2 = (0.43 M * 125 ml + 1.8 M * 17 ml) / 142 ml
Calculate the final concentration C2 to find the concentration of the resulting mixture.