Complete the reaction-
2F2(g)+2H2O(l)=?
4HF(g) + O2(g)
The reaction between 2 moles of fluorine gas (F2) and 2 moles of water (H2O) can be completed as follows:
Step 1: Write the balanced equation for the reaction.
2F2(g) + 2H2O(l) → 4HF(aq) + O2(g)
Step 2: Identify the products formed.
The reaction produces 4 moles of hydrofluoric acid (HF) and 1 mole of oxygen gas (O2).
Therefore, the complete reaction is:
2F2(g) + 2H2O(l) → 4HF(aq) + O2(g)
To complete the reaction, we need to determine the products formed when 2F₂(g) and 2H₂O(l) react.
First, let's identify the elements involved in the reaction:
- F₂: This is a diatomic molecule of fluorine gas.
- H₂O: This is water, composed of two hydrogen atoms and one oxygen atom.
Now, let's analyze the possible reactions between fluorine gas and water.
One possible reaction is the displacement of hydrogen by fluorine, forming hydrogen fluoride (HF) and releasing oxygen gas (O₂):
2F₂(g) + 2H₂O(l) → 4HF(aq) + O₂(g)
Another possible reaction is the formation of hypofluorous acid (HOF) and releasing hydrogen gas (H₂):
2F₂(g) + 2H₂O(l) → 4HOF(aq) + H₂(g)
These are the two most common reactions between fluorine gas and water. However, the reaction can vary depending on the conditions and the presence of catalysts.
Therefore, the complete reaction between 2F₂(g) and 2H₂O(l) could be either:
- 2F₂(g) + 2H₂O(l) → 4HF(aq) + O₂(g)
- 2F₂(g) + 2H₂O(l) → 4HOF(aq) + H₂(g)
The specific reaction would depend on the prevailing conditions and factors governing the reaction.