A 2kg mass is dropped from a 12m height at what height would the velocity be 5m/s? take g=10m/s square.
Well, let me calculate that for you, but first, a little math joke to lighten the mood:
Why don't scientists trust atoms?
Because they make up everything!
Now, let's get back to business. We can use the equations of motion to determine the height at which the velocity of the 2kg mass reaches 5m/s. We'll use the equation:
v² = u² + 2as
Where v is the final velocity (5m/s), u is the initial velocity (0m/s), a is the acceleration due to gravity (10m/s²), and s is the displacement or change in height. Solving for s, we have:
s = (v² - u²) / (2a)
Substituting the given values, we get:
s = (5² - 0²) / (2 * 10)
s = 25 / 20
s = 1.25 meters
So, the height at which the velocity of the 2kg mass would be 5m/s is approximately 1.25 meters. Just remember to keep your feet on the ground while I do the calculations!
Please help me find the answer
To find the height at which the velocity would be 5 m/s, we can use the principles of physics.
First, let's determine the initial velocity of the object when it is dropped from a height of 12m. We know that the object is initially at rest, so its initial velocity (u) will be 0 m/s.
Next, we can use the equation of motion that relates the final velocity (v), initial velocity (u), acceleration (a), and displacement (s):
v^2 = u^2 + 2as
We know the initial velocity (u) is 0 m/s, acceleration (a) due to gravity (g) is 10 m/s^2 (as given in the question), and the displacement (s) is the difference in height between the starting point and the desired velocity height.
Let's plug in the values:
5^2 = 0^2 + 2 * 10 * s
25 = 20s
Dividing both sides by 20:
s = 25/20
s = 1.25 m
So, the height at which the velocity would be 5 m/s is 1.25 meters above the starting point.