a jewelry salesman can earn either a salary of$2500 a month or a salary of $1000 a month plus 10% of all sales. how much does he have to sell for the second choice to earn more than the first choice

When does

.2 s + 1000 ≥ 2500 ?
where s represents sales.

15000

To determine how much the jewelry salesman has to sell for the second choice to earn more than the first choice, we need to compare the two scenarios.

First Choice: $2500 per month
Second Choice: $1000 per month plus 10% of sales

Let's assume the amount of sales the salesman has to make is "x" dollars. In this case, his earnings from the second choice would be $1000 plus 10% of "x". So the equation for the second choice would be:

Earnings from second choice = $1000 + 0.10x

To find the threshold where the second choice earns more than the first choice ($2500 per month), we can set up an inequality:

Earnings from second choice > Earnings from first choice

$1000 + 0.10x > $2500

Now, we can solve this inequality to find the value of "x":

$1000 + 0.10x > $2500
0.10x > $2500 - $1000
0.10x > $1500
x > $1500 / 0.10
x > $15,000

Therefore, the jewelry salesman would have to sell more than $15,000 worth of jewelry for the second choice to earn more than the first choice of a $2500 salary per month.