Two planes, which are
2660 miles apart, fly toward each other. Their speeds differ by 65 mph. If they pass each other in 4 hours, what is the speed of each?
If the slow plane's speed is x mi/hr, then since distance=speed*time,
4x + 4(x+65) = 2660
3oo and 365
To find the speed of each plane, we can set up a system of equations.
Let's call the speed of the slower plane "x" mph.
Since the speed of the faster plane differs by 65 mph, the speed of the faster plane would be "x + 65" mph.
When the planes are flying towards each other, the sum of their distances covered will be equal to the total distance between them.
We can use the formula: distance = speed × time
Distance covered by the slower plane = speed of slower plane × time = x × 4
Distance covered by the faster plane = speed of faster plane × time = (x + 65) × 4
The sum of these distances is equal to the total distance between them, which is 2660 miles.
Therefore, we can set up the equation: 4x + 4(x + 65) = 2660
Next, let's solve the equation:
4x + 4x + 260 = 2660
8x + 260 = 2660
8x = 2660 - 260
8x = 2400
x = 2400/8
x = 300
Therefore, the speed of the slower plane is 300 mph, and the speed of the faster plane is 300 + 65 = 365 mph.