Two trucks A and B each travelling at 40 km/hr, move towards each other . At the instance when the two trucks are at a distance 50 km from one another, a car moving at 60 km/hr overtakes A. How far behind the car is A at the point when the car meets B?
At the instant of the car overtaking truck A, the car is approaching truck B at 60 + 40 = 100 km/h. Since truck B is 50 km away, the car will meet it in 0.5 hours. During that period, the car will be leaving truck A behind at 60 - 40 = 20 km/h. Therefore the car will leave truck A behind by (20)(0.5) = 10 km.
The two trucks meet in .625 hrs. At that time truck A has moved 25 km. The car has moved 37.5 km. So the two are 12.5 km apart.
pls can u work it out? I don't understand how u got the answer.
To solve this problem, let's break it down step by step:
Step 1: Calculate the relative speed of the two trucks.
Since the trucks are moving towards each other, their relative speed is the sum of their individual speeds. In this case, truck A is moving at 40 km/hr and truck B is also moving at 40 km/hr. So, the relative speed of the two trucks is 40 km/hr + 40 km/hr = 80 km/hr.
Step 2: Determine the time it takes for the car to overtake truck A.
Since the car is moving at 60 km/hr and overtaking truck A, we need to calculate the time it takes for the car to cover the distance between them. The formula to calculate time is distance divided by speed. In this case, the distance is 50 km and the speed is 60 km/hr. Therefore, the time it takes for the car to overtake truck A is 50 km / 60 km/hr = 5/6 hours.
Step 3: Calculate the distance covered by truck A when the car meets truck B.
To calculate the distance covered by truck A, we need to multiply the time it takes for the car to overtake truck A with the speed of truck A. The time is 5/6 hours and the speed of truck A is 40 km/hr. Therefore, the distance covered by truck A when the car meets truck B is (5/6) hours * 40 km/hr = 200/6 km = 33.33 km (rounded to two decimal places).
Step 4: Determine how far behind truck A the car is at the point of meeting truck B.
Since the car has already overtaken truck A, the distance between the car and truck A at the point of meeting truck B is the equivalent of the distance that truck A has covered after being overtaken. This distance is 33.33 km.
Therefore, at the point when the car meets truck B, truck A is 33.33 km behind it.
v1=v2
distance apart is 50km,then each truck has 25km to cover
taking one truck (A): t=s/v t=25km/40kmhr^-1= 5/8hrs for the trucks .
in 5/8hrs, Overtaking car has speed of 60km/hr.
now s=vt
s=60km/hr x 5/8hr= 37.5km.
in 5/8hr car A= 25km
car C=37.5km. difference is. 12.5km
v1=v2
distance apart is 50km,then each truck has 25km to cover
taking one truck (A): t=s/v t=25km/40kmhr^-1= 5/8hrs for the trucks .
in 5/8hrs, Overtaking car has speed of 60km/hr.
now s=vt
s=60km/hr x 5/8hr= 37.5km.
in 5/8hr car A= 25km
car C=37.5km. difference is. 12.5km
but car C will collide with car B when C is at 37.5km, A is at 12.5km (d/4 B is also at 12.5km)
difference in distance is 37.5-12.5= 25km