A sector of a circle of radius 7cm subtending an angle of 270 degree at centre of the circle is use to form a cone?

(A)find the base radius of the cone.
(B)calculate the area of the base of the cone.

270/360 *2*22/7*7=33

2πr=33
2*22/7=33
44/7*x=33
X=33*7/44
X=5.25

270/360

(b)

πr^2
=22/7×21/4×21/4
=693/8cm^2 ~87cm^2

what is the answer

Yes

Solve

To solve this problem, we need to use the properties of a sector of a circle and relate it to the cone formed.

A) The base radius of the cone is equal to the radius of the circle which forms the sector. In this case, the radius of the sector is given as 7 cm. Therefore, the base radius of the cone is also 7 cm.

B) The area of the base of the cone can be determined using the formula for the area of a circle, which is πr^2, where r is the radius of the circle.

Since the base radius of the cone is 7 cm (as we found in part A), we can substitute this value into the formula:

Area of the base of the cone = π(7 cm)^2

Calculating this, we get:

Area of the base of the cone = 49π cm^2

So, the area of the base of the cone is 49π square centimeters.

Angle/360=length Of An Arc/pi*diameter

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