Can you tell me if this is correct.
Solve.x^2+6x-4=0 the answer I got is x=-3+sqrt13,-3-sqrt13
yes
thanks
To check if your answer is correct, we can use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In your equation, we have:
a = 1 (coefficient of x^2)
b = 6 (coefficient of x)
c = -4 (constant term)
Substituting these values into the quadratic formula, we get:
x = (-(6) ± √((6)^2 - 4(1)(-4))) / (2(1))
x = (-6 ± √(36 + 16)) / 2
x = (-6 ± √52) / 2
x = (-6 ± 2√13) / 2
x = -3 ± √13
Thus, your answer x = -3 + √13 and x = -3 - √13 is correct.