Math

3 cos (ωt + 2) + 4 sin (ωt + 1) as A cos (ωt + φ) .


A = ? φ= ?

asked by jiya
  1. try the addition formulas:
    3 cos (ωt + 2) = 3(cosωt cos2 - sinωt sin2)
    4 sin(ωt+1) = 4(sinωtcos1 + cosωtsin1)

    adding them up you get

    3cosωtcos2+4cosωtsin1
    + 4sinωtcos1 - 3sinωtcos2

    Now, according to wolframalpha.com, that gives

    A = √(25-24sin(1))
    tanφ =

    sec(1)(4sin(1)+3cos(2))
    -------------------------------
    4 - 6sin(1)

    so φ ≈ -3.736

    See

    http://www.wolframalpha.com/input/?i=3+cos+%28t+%2B+2%29+%2B+4+sin+%28t+%2B+1%29

    But I don't see any clear path to getting there.

    posted by Steve

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