Using calculations, determine how you would make a 525 ml pg a 0.50 M solution of Cl- ions using CaCl2.

I am unsure how to do this question, I was going to use C1V1=C2V2 but with this I would be missing the first part of the equation. If that is the case, would I assume the solution was originally 1 M CaCl2 and find the volume necessary to make 525 ml of a 0.50 M solution?

C1V1=C2V2
(1 M)(V1)=(0.50 M)(525 ml)
V1 = (0.50 M)(525 ml)/(1 M)
V1 = 262.5 ml of 1 M CaCl2.

525 mL of .5 M solution contains

(.525 * .5) moles of solute

since you get 2 Cl-ions from each CaCl₂
you will need...(.525 * .5 * .5) moles of CaCl₂, dissolved in 525 mL of solution
molar mass of CaCl₂ is 111 g

(.5 * .5 * .525 * 111) g of CaCl₂

To make a 525 ml solution with a concentration of 0.50 M Cl- ions using CaCl2, you can follow these steps:

1. Firstly, you need to determine the molar mass of CaCl2, which is 40.08 g/mol for Ca and 35.45 g/mol for Cl. Since CaCl2 contains two Cl- ions, the molar mass of Cl- is 35.45 g/mol x 2 = 70.90 g/mol.

2. Next, calculate the number of moles of Cl- ions you need to make a 0.50 M solution. To do this, you can use the formula: moles = concentration (M) x volume (L). Since the volume is given in milliliters (ml), you need to convert it to liters (L) by dividing by 1000.

moles of Cl- = 0.50 M x (525 ml / 1000) L
moles of Cl- = 0.2625 mol

3. Since CaCl2 dissociates into one Ca2+ ion and two Cl- ions, the number of moles of CaCl2 needed is twice the moles of Cl- ions required.

moles of CaCl2 = 2 x moles of Cl-
moles of CaCl2 = 2 x 0.2625 mol
moles of CaCl2 = 0.525 mol

4. Finally, calculate the mass of CaCl2 needed using the formula: mass = moles x molar mass.

mass of CaCl2 = 0.525 mol x 110.98 g/mol (molar mass of CaCl2)
mass of CaCl2 = 58.1685 g (rounded to four decimal places)

Therefore, to prepare a 0.50 M solution of Cl- ions using CaCl2, you will need approximately 58.1685 grams of CaCl2.

To make a 525 ml solution of 0.50 M Cl- ions using CaCl2, you can follow the steps below:

1. Determine the molecular weight of CaCl2: Ca has a atomic weight of 40.08 g/mol, and Cl has an atomic weight of 35.45 g/mol. So the molecular weight of CaCl2 is (40.08 g/mol) + 2 * (35.45 g/mol) = 110.98 g/mol.

2. Calculate the number of moles of Cl- ions needed in the final solution: Since CaCl2 dissociates into one Ca2+ ion and two Cl- ions in solution, we need to calculate the number of moles of Cl- ions required. The Molarity (M) of the Cl- ions in the final solution is given as 0.50 M. Therefore, the number of moles of Cl- ions needed is (0.50 M) * (0.525 L) = 0.2625 moles.

3. Calculate the mass of CaCl2 required: The molar ratio between Cl- ions and CaCl2 is 2:1. So, the number of moles of CaCl2 required is half the number of moles of Cl- ions needed. Therefore, the number of moles of CaCl2 required is 0.2625 moles / 2 = 0.13125 moles.

4. Calculate the mass of CaCl2 required using the molecular weight: The mass of CaCl2 required is the number of moles multiplied by the molecular weight. Therefore, the mass of CaCl2 required is 0.13125 moles * 110.98 g/mol = 14.54 grams.

So, to make a 525 ml solution of 0.50 M Cl- ions using CaCl2, you would need to measure out 14.54 grams of CaCl2 and dissolve it in enough water to make a final volume of 525 ml.