A BODY OF MASS 4OOKG WITH VELOCITY OF 5M/S COLLIDE WITH A STATIONARY BODY 500KG IF THE TWO BODY AFTER IMPACT CALCULATE THE MAGNITUDE OF THEIR COMMON VELOCITY.
220KG
Answering yourself. Very strange!
To calculate the magnitude of their common velocity after the impact, we can use the law of conservation of momentum. According to this law, the total momentum of an isolated system remains constant before and after a collision.
The momentum (p) of an object is defined as the product of its mass (m) and velocity (v): p = m * v.
Before the collision, the momentum of the first body can be calculated as:
Momentum of the first body before collision = mass of the first body * velocity of the first body
= 400 kg * 5 m/s
= 2000 kg·m/s
The momentum of the second body is zero since it is stationary.
After the collision, the total momentum remains the same. Therefore, the sum of the individual momentums of the two bodies after the collision is equal to the momentum before the collision:
Momentum of the first body after collision + Momentum of the second body after collision = 2000 kg·m/s
Let's assume the common velocity of the two bodies after the collision is represented by 'v'.
Using the momentum formula, we can calculate the momentum of the first body after the collision:
Momentum of the first body after collision = mass of the first body * velocity of the first body after collision
= 400 kg * v
Similarly, for the second body:
Momentum of the second body after collision = mass of the second body * velocity of the second body after collision
= 500 kg * v
Now we can set up an equation using the conservation of momentum principle:
(400 kg * v) + (500 kg * v) = 2000 kg·m/s
900 kg * v = 2000 kg·m/s
Divide both sides of the equation by 900 kg to solve for 'v':
v = 2000 kg·m/s / 900 kg
v ≈ 2.22 m/s
Therefore, the magnitude of their common velocity after the impact is approximately 2.22 m/s.