A ball is thrown vertically upword with an initial velocity of 40m/s (1) calculate 1 it velocity after 3secs (2) the maximum height attend and the time taken to reach the maximum height (3) the total taken for the ball to return to the grand again
1) v = vo + at
v = 40 - 9.8*3
2) x = v^2/(2*9.8)
t = vo/t
3) t = twice the max height time.