A bag contains 8 blue coins and 6 red coins. A coin is removed at random and replaced by three of the other color.

a) What is the probability that the removed coin is blue?
b) If the coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?
c) If the coin removed is red, what is the probability of drawing a red coin after three blue coins are put in the bag to replace the red one?
THANK YOU!!!

Your all wrong! Becuase the answer changes every time you completely get it wrong!

bro just shut up its a new year and jusst gimme the answer aqlready

It is

4/7
9/16
5/16

You are all wrong it is 3/7.

ITS 9/16

its 4/17 people

3/10

The probability of drawing a red coin after three blue coins are put in the bag to replace the red one that has been removed is

8+3=11 6-1=5 11+5=16 5/16

9/16