Assume the reaction of 55.25 g of Ge in the following reaction to determine the other quantities.
3Ge + 2N2 -> 1Ge3N4
To determine the other quantities in the reaction, we need to use the concept of stoichiometry, which relates the amounts of reactants and products in a chemical reaction.
1. Convert grams of Ge to moles:
To do this, we need to know the molar mass of Ge. The molar mass of Ge is 72.63 g/mol.
Using the given mass of 55.25 g, we can calculate the number of moles of Ge:
moles of Ge = mass of Ge / molar mass of Ge
moles of Ge = 55.25 g / 72.63 g/mol
2. Apply the stoichiometry of the balanced equation:
According to the balanced equation:
3Ge + 2N2 -> 1Ge3N4
This equation tells us that 3 moles of Ge react with 2 moles of N2 to produce 1 mole of Ge3N4.
3. Determine the moles of N2 consumed and the moles of Ge3N4 produced:
From the stoichiometry of the balanced equation, we can determine the moles of N2 consumed and the moles of Ge3N4 produced relative to the moles of Ge reacted.
Since the stoichiometric ratio between Ge and N2 is 3:2, and the stoichiometric ratio between Ge and Ge3N4 is 3:1:
moles of N2 = moles of Ge × 2/3
moles of Ge3N4 = moles of Ge × 1/3
4. Convert moles to grams:
To determine the mass of N2 and Ge3N4, we need to convert moles back to grams using their respective molar masses. The molar mass of N2 is 28.02 g/mol, and the molar mass of Ge3N4 is 164.68 g/mol.
mass of N2 = moles of N2 × molar mass of N2
mass of Ge3N4 = moles of Ge3N4 × molar mass of Ge3N4
By following these steps, you can determine the mass of N2 consumed and the mass of Ge3N4 produced in the reaction.