If the maximum current in an LR circuit is 2 A what is the instantaneous current at t= time constant of the circuit?
at one time constant (τ) the current is approx. 63% of max
Thnx a lot @Scott
To determine the instantaneous current at the time constant of an LR circuit, we need to understand the behavior of the circuit and the relationship between time and current.
In an LR circuit, the current buildup is not instantaneously achieved when the circuit is switched on. Instead, the current slowly increases over time due to the presence of inductance in the circuit.
The time constant (τ) of an LR circuit is determined by the product of the resistance (R) and the inductance (L), which is given by the formula: τ = L/R.
At the time constant (t = τ), the current in the LR circuit has reached approximately 63.2% (1 - 1/e) of its maximum value.
Given that the maximum current in the LR circuit is 2 A, we can calculate the instantaneous current at the time constant by multiplying the maximum current by the 63.2% value.
Instantaneous current at t = time constant ≈ 2 A * 0.632 ≈ 1.264 A