I'm finishing my math 20 Pure. This is my last 20 course then i have 30's. Also I have to work a full time job so that I can live on my own with my boy. So it is tough but I'm doing alright. What about you?
wow, okay i have no idea what all that is but good luck. i'm in precalculas. so what is your next problem?
Make a conjecture about the next 3 terms in the sequence 1,5,2,8,3,11....
Explain your reasoning.
ahh. i see. okay so this one, is
1, 5, 2, 8, 3, 11
okay this one is a bit igreular, for the first number, 1, add 4, the second number is 5 and your going to subtract 3, the third number is 2 and your going to add six, the fourth number is 8 and your going to subtract 5. do you see the pattern?
1, (1+4)=
5, (5-3)=
2, (2+6)=
8, (8-5)=
3, (3+8)=
11, (11 this one is giong to be subtraction ?) what do you think?
oh the pattern is + - + -????? But how do you write that as a conjecture that it will be a pattern of plus and minus???
good! yeah that is part of the pattern. um, i'm still not exactly sure what you mean by conjecture. how does one usually write a "conjecture"? what goes in this "conjecture"? numbers? words? equations? what exactly?
usually like this:
eg.) Start with 3; double the term = next term.
ahh! gotcha! i hope. lol but i do remember doing something like that. what math are you in? and yes i'd be happy to answer any quesiotns you may have. i treid to post it but i'm not sure if it went through on the first postings we exchanged.
If n is a natural number, what values of n make the following compound sentance true?
A natural number, n, is a factor of 6 or it is a prime less than 11.
its been a while since i've done primes and factors, but i would guess 3 and 2. both are factors of 6 and primes less than 11. but you said or? then that would be 2, 3, 5, 7, and i believe that's it. remember prime numbers are numbers where only 1 and itself can go into it evenly. 2 is a prime because only 1 and 2 go go into 2 evenly, same for 3, 5, and 7. 9 is commonly mistaken as a prime number but it is not because 3 can go into 9 evenly.
To make the compound sentence true, we need to find the values of n that satisfy both conditions: being a factor of 6 and being a prime less than 11.
First, let's consider the factors of 6. The factors of 6 are 1, 2, 3, and 6. So any value of n that is 1, 2, 3, or 6 will satisfy the first condition.
Now let's consider the primes less than 11. The primes less than 11 are 2, 3, 5, 7. So any value of n that is 2, 3, 5, or 7 will satisfy the second condition.
To find the values of n that satisfy both conditions, we look for the numbers that are common in both lists. In this case, the values that satisfy both conditions are 2 and 3. These are the only values of n that make the compound sentence true.