a jar is 6/8 full of water.if 3liters is poured making it 3/8full.how much liter will be needed to make the jar full?
So if the content changed from 6/8 full to 3/8, the water was poured out not poured in.
So the change is 3/8 of the capacity
let that capacity be x litres
(3/8)x = 3
x = 3(8/3) = 8 litres
so 5 litres will be needed to make the jar full.
btw, "how much liter will be needed " is poor grammar, say
"how many litres will be needed ..."
To solve this problem, we need to find out how much additional water is needed to make the jar full.
We know that initially, the jar is 6/8 full of water, which can be simplified to 3/4.
If 3 liters of water are poured into the jar, making it 3/8 full, we can set up the following equation:
3/4 + 3 = 3/8 + x
To add the fractions on the right side, we need to find a common denominator, which in this case is 8. Multiplying the numerator and denominator of 3/8 by 2, we get:
3/4 + 3 = 3/8 + (3/8 * 2/2)
3/4 + 3 = 3/8 + 6/8
3/4 + 3 = 9/8
Now, let's solve the equation:
3/4 + 3 = 9/8
To add fractions, we need a common denominator. The least common multiple of 4 and 8 is 8, so we can rewrite the equation as:
(3/4 * 2/2) + 3 = 9/8
6/8 + 3 = 9/8
Now we can add the fractions:
(6 + 3) / 8 = 9/8
9/8 is the final fraction representing the fraction of the jar that is full after pouring 3 liters of water.
To determine how much additional water is needed to make the jar full, subtracting from 1 (since a full jar is equivalent to 1):
1 - 9/8 = 8/8 - 9/8
1 - 9/8 = -1/8
Since we received a negative value, it means that the jar is already more than full. In other words, no additional water is needed to make the jar full.
Therefore, 0 liters of water will be needed to make the jar full.