(1/3)LN27 + 2LNx = LN(2-x)
i think i just need help getting started.
To solve the given equation (1/3)LN27 + 2LNx = LN(2-x), you can use the properties and rules of logarithms to simplify the equation. Here are the steps to get started:
Step 1: Simplify the equation using logarithmic properties:
- Rewrite LN27 as LN(3^3), since 27 can be expressed as 3 raised to the power of 3.
- Apply the logarithm property, LN(a^b) = b * LN(a), to rewrite the equation as LN(3) + LN(3) + 2LN(x) = LN(2-x).
Step 2: Combine like terms:
- Add the terms with the same base, LN(3), to get 2LN(3) + 2LN(x) = LN(2-x).
Now that we have simplified the equation, we can move on to solving it.