51J of heat added to an aluminum can with a mass of 25.5 g what is temperature change if specific heat capacity is 0.903 J/ g degrees Celsius?
To calculate the temperature change, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat added (in Joules)
m is the mass of the aluminum can (in grams)
c is the specific heat capacity of aluminum (in J/g°C)
ΔT is the temperature change (in °C)
Given:
Q = 51 J
m = 25.5 g
c = 0.903 J/g°C
Rearranging the formula, we have:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = 51 J / (25.5 g * 0.903 J/g°C)
Simplifying the equation:
ΔT = 2°C
Therefore, the temperature change of the aluminum can is 2°C.
To find the temperature change of the aluminum can, we can use the equation:
Q = m * c * ΔT
Where:
Q is the heat added (in Joules),
m is the mass of the aluminum can (in grams),
c is the specific heat capacity of aluminum (in J/g °C),
ΔT is the change in temperature (in °C).
In this case, Q is given as 51J, the mass of the aluminum can (m) is 25.5g, and the specific heat capacity (c) is 0.903J/g°C.
Let's plug in the values and solve for ΔT:
51J = 25.5g * 0.903J/g°C * ΔT
To isolate ΔT, we divide both sides of the equation by (25.5g * 0.903J/g°C):
ΔT = 51J / (25.5g * 0.903J/g°C)
Calculating this equation gives us the temperature change, which is the ΔT:
ΔT = 2°C
Therefore, the temperature change of the aluminum can is 2°C when 51J of heat is added.