Are you sure that's how you do #4 because they have 2 different directions.
I need physics help. I don't understand how to do these questions. Can someone show me what I should use? and explain. I'll do calculations by myself.
A stationary curling stone is struck in a glancing collision by a second curling stone of equal
mass. If the first stone moves away at a velocity of 0.92 m/s [N71oW] and the second stone
moves away at a velocity of 1.25 m/s [N44oE], what was the initial velocity of the second stone?
(5 marks)
2. A billiard ball (0.62 kg) with a velocity of 2.0 m/s [N] hits another ball and has a velocity of 1.7
m/s [E] after the collision. Determine the impulse on the ball and the average force exerted on it
during the collision if the duration of the collision was 0.0072 s. (5 marks)
3. Two billiard balls of equal mass undergo a head on collision. The red ball is travelling at 2.1
m/s [right] and hits the blue ball travelling at 3.0 m/s [left]. If the speed of the red ball after the
collision is 3.0 m/s [left], determine the velocity of the blue ball after the collision. (5 marks)
4. A car with a mass of 1800 kg is initially travelling with a velocity of 22 m/s [N] when it collides
with a truck with a mass of 3200 kg traveling with a velocity of 14 m/s [E]. If the two vehicles
become attached during the collision, determine their final velocity. (5 marks)
Physics - Henry, Wednesday, January 27, 2016 at 10:57pm
1. M1 = M2 = M.
Unless otherwise stated, all angles are measured CCW from +x-axis.
M*V1 + M*V2 = M*V3 + M*V4.
M*0 + M*V2 = M*0.92m/s[161o] + M*1.25m/s[46o].
M*V2 = 0.92M[161o] + 1.25M[46o].
Divide both sides by M and solve for V2
V2 = -0.87+0.30i + 0.87+0.90i =
1.20i = 1.20m/s[90o].
Physics - Henry, Wednesday, January 27, 2016 at 11:24pm
3. M*V1 + M*V2 = M*V3 + M*V4.
M*2.1 - M*3 = -M*3 + M*V4.
V4 = ?
4. M1*V1 + M2*V2 = M1*V + M2*V.
1800*22i + 3200*14 = 1800V + 3200V.
Divide both sides by 100 and solve for v.
4.
initial momentum N = 1800
Hey, I just did this
http://www.jiskha.com/display.cgi?id=1454030373
To solve these physics questions, you need to understand the principles of conservation of momentum and impulse-momentum theorem.
1. For the first question, you can use the equation for the conservation of momentum: M1*V1 + M2*V2 = M1*V3 + M2*V4. Here, M1 and M2 are the masses of the two curling stones, V1 and V2 are their initial velocities, and V3 and V4 are their final velocities after the collision. Since the second stone is initially stationary (0 m/s), the equation reduces to: M1*V1 = M1*V3 + M2*V4. By substituting the given values, you can solve for V4, which is the initial velocity of the second stone.
2. For the second question, you can use the impulse-momentum theorem: Impulse = Force * Time = Change in Momentum. The impulse experienced by the ball can be calculated by multiplying the force exerted on it by the duration of the collision. Since force is the rate of change of momentum, you can find it by dividing the change in momentum by the duration of the collision. Given the mass, initial velocity, final velocity, and duration of the collision, you can calculate the impulse and average force.
3. For the third question, you can use the conservation of momentum equation again: M1*V1 + M2*V2 = M1*V3 + M2*V4. Here, M1 and M2 are the masses of the billiard balls, V1 and V2 are their initial velocities, and V3 and V4 are their final velocities after the collision. In a head-on collision, the initial velocity of one ball is considered negative, so the equation becomes: M1*V1 - M2*V2 = -M1*V3 + M2*V4. By substituting the given values, you can solve for V4, which is the velocity of the blue ball after the collision.
4. For the fourth question, you can again use the conservation of momentum equation: M1*V1 + M2*V2 = (M1 + M2)*V. Here, M1 and M2 are the masses of the car and truck, V1 and V2 are their initial velocities, and V is their final velocity after becoming attached. By substituting the given values, you can solve for V, which is their final velocity.
Remember to carefully read the question and use the correct equations based on the given information. Good luck with your calculations!