In a thundercloud there may be an electric

charge of 46 C near the top of the cloud and
−46 C near the bottom of the cloud.
If these charges are separated by about
6 km, what is the magnitude of the electric
force between these two sets of charges?
The value of the electric force constant is
8.98755 × 109 N · m2
/C
2
.
Answer in units of N.
please help me

F = k Q1 Q2 / d^2

= 9*10^9 (46)(46)/(36*10^6)

Sure, I'd be delighted to help you with your question! But before we proceed, let me ask you a question. Why did the thundercloud refuse to go to the comedy club? Because it heard the jokes were shocking! Now, let's calculate the magnitude of the electric force between these two sets of charges.

The electric force between two charges can be calculated using Coulomb's Law, which states that the force is equal to the product of the charges divided by the square of the distance between them, multiplied by the electric force constant.

So, in this case, we have a charge of 46 C near the top of the cloud and -46 C near the bottom of the cloud, separated by a distance of 6 km (which can be converted to meters as 6000 m).

Plugging in these values into Coulomb's Law, we get:

Electric force = (Charge 1 × Charge 2) / (Distance^2) × Electric force constant

Electric force = (46 C × -46 C) / (6000 m)^2 × 8.98755 × 10^9 N · m^2 / C^2

Electric force = (-2116 C^2) / (36000000 m^2) × 8.98755 × 10^9 N · m^2 / C^2

Now, let me calculate that for you and provide you with an answer. Drum roll, please... The magnitude of the electric force between these two sets of charges is approximately 5.27517 × 10^9 N. Ta-da! I hope that helps! Let me know if there's anything else I can assist you with.

To find the magnitude of the electric force between two charges, we need to use Coulomb's Law. Coulomb's Law states that the electric force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:
F = k * (q1 * q2) / r^2

Where:
F is the magnitude of the electric force
k is the electric force constant (8.98755 × 10^9 N·m^2/C^2)
q1 and q2 are the charges
r is the distance between the charges

In this case, the values are:
q1 = 46 C (near the top of the cloud)
q2 = -46 C (near the bottom of the cloud)
r = 6 km = 6000 m

Now we can calculate the magnitude of the electric force using the formula.

F = (8.98755 × 10^9 N·m^2/C^2) * ((46 C) * (-46 C)) / (6000 m)^2
F = (8.98755 × 10^9) * (-2116) / (3.6 × 10^7)
F = - 1904.00705 N

Therefore, the magnitude of the electric force between these two sets of charges is approximately 1904 N.

To calculate the magnitude of the electric force between the two sets of charges in the thundercloud, we can use the formula for the electric force:

F = k * (|q1| * |q2|) / r^2

where F is the electric force, k is the electric force constant (8.98755 × 10^9 N · m^2 / C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

In this case, we are given that there is a charge of +46 C near the top of the cloud and a charge of -46 C near the bottom of the cloud. Since the charges have the same magnitude, we can simply use 46 C for both |q1| and |q2|. The distance between the charges is given as about 6 km, which we'll need to convert to meters by multiplying by 1000.

Let's plug in the values into the formula:

F = (8.98755 × 10^9 N · m^2 / C^2) * (|46 C| * |46 C|) / (6 km * 1000)^2

First, let's calculate |46 C| * |46 C| = 46 C * 46 C = 2116 C^2.

Now let's calculate the distance in meters: 6 km * 1000 = 6000 m.

Plugging in these values into the formula:

F = (8.98755 × 10^9 N · m^2 / C^2) * (2116 C^2) / (6000 m)^2

Now we can calculate F.

F ≈ 1.2421 × 10^4 N

Therefore, the magnitude of the electric force between these two sets of charges in the thundercloud is approximately 1.2421 × 10^4 N.