Solve d following que usin substitution method....
3a=2b+1...equ1
3b=5a-3....equ2
a = (2/3) b + 1/3
use in eqn 2
3 b = 5 [(2/3) b + 1/3 ] - 3
3 b = (10/3)b + 5/3 - 3
9 b = 10 b + 5 - 9
b = 9-5
b = 4
3a = 2(4) +1 = 8+1
a = 3
3a=2b+1...equ1
3b=5a-3....equ2
use in eqn 2
3 b = 5 [(2/3) b + 1/3 ] - 3
3 b = (10/3)b + 5/3 - 3
9 b = 10 b + 5 - 9
b = 9-5
b = 4
3a = 2(4) +1 = 8+1
a = 3