# maths

a car weighing 1600kg moving with a velocity of 30 meter per second uniformly coming to rest in 20 seconds calculate
1, initial momentum
2, final momentum
3, rate of change of momentum
4,acceleration of the car
5, magnitude of the force apply

1. 👍 6
2. 👎 3
3. 👁 1,487
1. (1) 1600*30
(2) 0
(3) p = mv, so dp/dt = m dv/dt = 1600*(0-30)/(20-0) = -2400 kg-m/s
(4) see (3)
(5) F = ma

1. 👍 6
2. 👎 6
2. Samaj nahi aaya explain briefly

1. 👍 8
2. 👎 4
3. 1) initial momentum =mv
Mass =1600 kg
Velocity =30m/sec
=1600 *30=4800 kg m/s
2)final momentum=mv
If it is slowing down then the final velocity = 0m/Sec
Mass =1600kg
=mv
1600*0=0 kg m/sec
3)rate of change of momentum =m1u1 +m2u2=m1v1+m2v2
U = initial velocity =0m/sec
V=final velocity =30m/sec
Mass = 1600kg
1600*0+1600*0=1600*30+1600*30
0=4800+4800
Rate of change of momentum =9600

1. 👍 6
2. 👎 4
4. Ur ans 3 is wrong
Rate of change of momentum is 2400 N
Plz always check and then post, how can anyone be this much irresponsible

1. 👍 6
2. 👎 0
5. What is answer 4 and 5

1. 👍 2
2. 👎 0

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