A rectangular room is
6
6
meters longer than it is wide, and its perimeter is
28
28
meters. Find the dimension of the room.
The length is : meters and the width is meters.
I don't understand your notation.
Perhaps it comes out different on your own monitor.
Your previous post looks just like that too, you just changed the numbers.
To find the dimensions of the rectangular room, we can use the information given about its length and width.
Let's assume that the width of the room is x meters. According to the problem, the length of the room is 6 meters longer than the width. So, the length can be represented as (x + 6) meters.
The perimeter of a rectangle is calculated by adding up all its sides. In this case, the perimeter of the room is given as 28 meters. So, we can set up the equation:
2(width) + 2(length) = perimeter
Substituting the values we know:
2(x) + 2(x + 6) = 28
Simplifying the equation:
2x + 2x + 12 = 28
Combining like terms:
4x + 12 = 28
Now, we can isolate the variable:
4x = 28 - 12
4x = 16
Dividing both sides by 4:
x = 16/4
x = 4
So, the width of the room is 4 meters.
To find the length, we can substitute the width value into the equation for length:
Length = x + 6 = 4 + 6 = 10 meters.
Therefore, the dimensions of the room are:
Length = 10 meters
Width = 4 meters