the legth of a side of a square is represented by (3x-1). if the perimeter of the square is 68, find t
he value of x
4(3x-1) = 68
continue ....
perimeter of the square = 4a
a is the side of square
3x-1=68
solve the equ u get the ans :)
4(3x - 1) = 68
12x - 4 = 68
12x = 72
x = ?
sorry reiny is right 4(3x-1)=68
To solve this problem, we need to set up an equation using the information given.
The perimeter of a square is found by adding up the lengths of all four sides. Since all sides of a square are equal in length, we can say that the perimeter of a square is four times the length of one side.
Let's represent the length of a side as (3x - 1). Therefore, the perimeter of the square is:
Perimeter = 4 * (3x - 1)
We are given that the perimeter is 68. We can set up the equation:
68 = 4 * (3x - 1)
To solve for x, we can simplify and solve the equation step-by-step:
68 = 12x - 4 (distributed multiplication)
68 + 4 = 12x (added 4 to both sides)
72 = 12x (simplified)
Now, we can isolate x by dividing both sides of the equation by 12:
72 / 12 = x
6 = x
So, the value of x is 6.