Michelle had 12 girls and 36 boys show up for field day. She wanted to divide them into groups so that each group had the same number of girls and boys.
What is the greatest number of groups that Michelle can make if all of the children are in a group?
a.3
b.4
c.6
d.12
help pleseeeee
A
36/12 = 3
An airplane descended 149ft and rose 112 ft Write a number sentence to show the results.
who me
you have 12 girls
put one girl and 3 boys in each of 12 groups
total rise = 112 - 149
= -37
To solve this problem, we need to find the greatest common divisor (GCD) of the given numbers. The GCD represents the largest number that divides both 12 and 36 evenly.
To find the GCD, we can use the prime factorization method. We'll express both numbers as products of their prime factors:
12 = 2^2 * 3
36 = 2^2 * 3^2
Next, we find the highest power of each prime factor that appears in both numbers. In this case, the highest power of 2 is 2^2 and the highest power of 3 is 3^1.
To calculate the GCD, we multiply the shared prime factors with their highest powers:
GCD(12, 36) = 2^2 * 3^1 = 4 * 3 = 12
So the greatest number of groups that Michelle can make with an equal number of girls and boys is 12.
The correct answer is (d) 12.