the pressure at a point below a point below the surface of the sea is caused by both the height of the water above that and the air pressure on the surface of the sea. if the diver reaches a depth of 20m below the surface on the surface of the sea
Calculate The total pressure on him
density 1150
air pressure 1.0x10^5
g=9.8ms^-2
i am not sure how to work this question but so far i did this i multiplied the height and air pressure but that all.
pressure is measured in Newtons per square meter or Pascals
20 m below the surface, there are 20 cubic meters of water stacked up
20,000 kg * 9.8 m/s² = 2.0 x 10⁵ N
the water pressure is...2.0x10⁵ Pa
the total pressure is...3.0x10⁵ Pa
3. At what depth the water in the lake creates the pressure equal to atmospheric pressure of P0 = 105 Pa? Water density = 103 kg/m3. Free fall acceleration is g = 10 m/s2.
To calculate the total pressure on the diver, you need to consider both the weight of the water column above the diver and the atmospheric pressure.
The pressure due to the weight of the column of water can be calculated using the formula:
Pressure = density × gravity × height
First, convert the depth from meters to pascals (Pa) by multiplying by the density of water (1150 kg/m^3) and the acceleration due to gravity (9.8 m/s^2):
Depth = 20 m × 1150 kg/m^3 × 9.8 m/s^2
Next, calculate the pressure due to the weight of the water column:
Water Pressure = Depth × gravity
Now, add the air pressure to the water pressure to get the total pressure on the diver:
Total Pressure = Water Pressure + Air Pressure
Substituting the values:
Total Pressure = (Depth × density × gravity) + Air Pressure
= (20 m × 1150 kg/m^3 × 9.8 m/s^2) + 1.0 × 10^5 Pa
Simplifying the equation:
Total Pressure = 225,400 + 1.0 × 10^5 Pa
So, the total pressure on the diver would be 325,400 Pa.
To calculate the total pressure experienced by the diver, you need to consider both the pressure due to the height of the water above the diver and the pressure due to the air above the water. The total pressure (P) can be calculated using the following formula:
P = P_water + P_air
where:
P_water = ρ * g * h
P_air = air pressure
Given:
ρ (density of water) = 1150 kg/m^3
g (acceleration due to gravity) = 9.8 m/s^2
h (depth below the surface) = 20 m
Air pressure = 1.0 * 10^5 Pa
Step 1: Calculate the pressure due to the height of the water (P_water):
P_water = ρ * g * h
= 1150 kg/m^3 * 9.8 m/s^2 * 20 m
Step 2: Calculate the pressure due to the air (P_air):
P_air = 1.0 * 10^5 Pa
Step 3: Add the two pressures to get the total pressure:
Total Pressure (P) = P_water + P_air
Now, let's plug in the values and solve the equation:
P_water = 1150 * 9.8 * 20
P_water = 226,400 Pa
Total Pressure (P) = 226,400 + 1.0 * 10^5
Total Pressure (P) = 326,400 Pa
Therefore, the total pressure on the diver at a depth of 20m below the surface of the sea is 326,400 Pa.