A body initially at distance given an acceleration of 12/s2 (squared2 ). Find the velocity after it travelled 205.

Q2. A body moving in linear motion start with an initial acceleration after 205 was 12m/s2. What's the velocity at this instance?

To find the velocity of a body after it has traveled a certain distance, you need to use the equations of motion. There are three main equations of motion, but we will use the one that relates displacement (distance), initial velocity, final velocity, time, and acceleration:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity
a = acceleration
s = displacement (distance)

For the first question:
Given:
a = 12/s^2 (acceleration)
s = 205 (displacement)

We need to find the final velocity (v). But we also need the initial velocity (u) to use in the equation. Since the initial velocity is not given, let's assume it is zero. This means the body starts from rest.

Using the equation:
v^2 = u^2 + 2as

v^2 = 0 + 2 * (12/s^2) * 205
v^2 = 2 * 12 * 205 / s^2
v^2 = 24 * 205 / s^2
v^2 = 4920 / s^2

Now we can find the value of v by taking the square root:
v = √(4920 / s^2)

Substituting the value of s = 205:
v = √(4920 / 205)
v ≈ √24
v ≈ 4.899 m/s (rounded to three decimal places)

So, the velocity of the body after it has traveled 205 units is approximately 4.899 m/s.

For the second question:
Given:
a = 12 m/s^2 (acceleration)
s = 205 (displacement)

We need to find the velocity (v) at this instance. Now, we assume that the initial velocity is also given as zero.

Using the same equation:
v^2 = u^2 + 2as

v^2 = 0 + 2 * 12 * 205
v^2 = 2 * 12 * 205
v^2 = 4884

Taking the square root:
v = √4884
v ≈ 69.92 m/s (rounded to two decimal places)

So, the velocity of the body at this instance, after 205 units with an initial acceleration of 12 m/s^2, is approximately 69.92 m/s.