How many grams of CO2 (Mm = 44.0 g/mol) are produced in the combustion of 31.0 g of C4H10 (Mm = 58.1 g/mol)?
C4H10 + 9mO2 ==> 4CO2 + 10H2O
mols C4H10 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols C4H10 to mols CO2
Now convert mols CO2 to g CO2 by grams CO2 = mols CO2 x molar mass CO2
To determine the number of grams of CO2 produced in the combustion of C4H10, we first need to balance the chemical equation for the combustion reaction.
The balanced equation for the combustion of C4H10 is:
2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
From this equation, we can see that for every 2 moles of C4H10 combusted, we produce 8 moles of CO2.
To calculate the moles of C4H10, we use the formula:
moles = mass / molar mass
moles of C4H10 = 31.0 g / 58.1 g/mol = 0.533 moles
From the balanced equation, we know that for every 2 moles of C4H10, we produce 8 moles of CO2.
moles of CO2 = (moles of C4H10) * (8 moles of CO2 / 2 moles of C4H10) = 0.533 moles * 4 = 2.132 moles
Finally, we can calculate the mass of CO2 using the equation:
mass = moles * molar mass
mass of CO2 = 2.132 moles * 44.0 g/mol = 93.808 g
Therefore, 93.808 grams of CO2 are produced in the combustion of 31.0 grams of C4H10.
To find the number of grams of CO2 produced in the combustion of 31.0 g of C4H10, we need to use the balanced chemical equation for the combustion of C4H10. The equation is as follows:
C4H10 + O2 -> CO2 + H2O
From the equation, we can see that for every 1 mole of C4H10 (58.1 g), we will produce 4 moles of CO2 (44.0 g/mol). This is based on the stoichiometric coefficients of the balanced chemical equation.
To calculate the number of moles of C4H10, we can use the formula:
moles = mass / molar mass
moles of C4H10 = 31.0 g / 58.1 g/mol = 0.533 mol
Now, using the stoichiometric relationship from the balanced equation, we can determine the number of moles of CO2 produced:
moles of CO2 = moles of C4H10 x (4 moles CO2 / 1 mole C4H10)
= 0.533 mol x 4
= 2.13 mol
Finally, we can convert the moles of CO2 to grams using the formula:
mass = moles x molar mass
mass of CO2 = 2.13 mol x 44.0 g/mol
= 93.7 g
Therefore, in the combustion of 31.0 g of C4H10, approximately 93.7 grams of CO2 are produced.