The question is "Find parametric equations for the line with the given properties:

Slope -2, passing through (-10, -20)."
I don't even know where to begin, or what to do. Please help! This is an example problem, not the main homework problem, I just need to know how to do those kinds of problems.

To find the parametric equations for a line, you need to use the point-slope form of a line equation. The point-slope form is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope of the line.

In this case, you are given the slope as -2 and a point on the line as (-10, -20). Now, substitute these values into the point-slope form:

y - (-20) = -2(x - (-10))

Simplify this equation:

y + 20 = -2(x + 10)

Next, we can rewrite this equation in slope-intercept form (y = mx + b) by simplifying further:

y + 20 = -2x - 20

Subtract 20 from both sides:

y = -2x - 40

Now, to express the line in parametric form, we can use the following equations:

x = x1 + at
y = y1 + bt

where (a, b) are any real numbers and (x1, y1) are the coordinates of any point on the line.

Let's choose a = 1 and b = -2 for simplicity. We can use the point (-10, -20) as the initial point.

So, the parametric equations for the line passing through (-10, -20) with a slope of -2 would be:

x = -10 + t
y = -20 - 2t

where t is any real number.

first, look up the definition of Parametric equation. It is a fancy term for something like this:

y=mx+b
m slope is -2, so put in the point (-10,-20) and solve for b

-20=2*(-10)+ b
b=0
y=2x