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Can you please help me in determining the 10th and 21st term of each arthmetic sequence
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Determine the 10th 21st term of arithmetic sequence
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depends on the sequence
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5 times the 5th term of arthmetic progression is equa to 10 times the 10th term. Find the common difference and the first term
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5(a+4d) = 10(a+9d) 5a+20d = 10a+90d a = -14d So, there is no unique solution. Some examples are a =
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The 3rd term of arthmetic sequence is 3/4th of 6th term.and their sum is 60.find a,d and nth term.
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a + 2 d = (3/4)[ a + 5d ] and 2 a + 7 d = 60 ------------------------ (1/4 a -7/4 d = 0 or 1 a - 7 d
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In an arthmetic sequence, the fourth term is 84 and the tenth term is 60. Find the maximum possible partial sum.
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a+3d = 84 a+9d = 60 -6d = 24 d = -4 a = 96 Since the terms decrease, the maximum partial sum is just
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Samantha is working on a math problem involving an arithmetic sequence. The first term of the sequence is 3 1/2 and the common
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you should have done: 10th_term = 3 1/2 + 9 * (2 1/3) = 3 1/2 + 18 9/3 = 3 1/2 + 21 = 24 1/2
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Determine the 10th and 21st terms of the arithmetic sequence- 4+7x, 5+9x, 6+11x
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5+9x - (4+7x) = 1+2x a = 4+7x d = 1+2x T10 = a+9d = 4+7x + 9(1+2x) = 13+25x T21 = a+20d = 4+7x +
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Write an expression to describe the sequence below, and then find the 10th term. Use n to represent the position of a term in
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The expression to describe the sequence is -6n. To find the 10th term, substitute n = 10 into the
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State whether the sequence is arithmetic or geometric, write a recursive and explicit formula and find the 10th term.
81, -27, 9,
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recursive: it just describes the pattern "to get a new term, multiply the previous by -1/3 so
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